Ruthenium (I) complexes with 4-ethoxy-phenyl tellurol : X-ray crystal structure of complex [Ru2(CO)₄(μ-TeC₆H₄OCH₂CH₃-4)₂ (μ-dppm)] (dppm=Ph₂PCH₂PPh₂)

Abstract

The reaction of [Ru₃(CO)₁₀(μ-dppm)] (dppm= Ph₂PCH₂PPh₂) with two molar equivalents of Te₂Ar₂ (Ar = C₆H₄OCH₂CH₃-4) in refluxing THF for 6 h gave the known complex [Ru₂ (C O)₄(μ-TeAr)(μ-dppm)] <b>1</b>¹ together with two new complexes [Ru₂(CO)₆(μ-TeAr)₂] <b>2</b> and <i>cis</i>-[Ru(CO)₄(η¹-TeAr)₂] <b>3</b>. Complex <b>1 </b>has been structurally characterized by X-ray crystallography. Both Ru atoms are in highly distorted octahedral geometry. For each Ru, two CO groups in <i>cis </i>positions, the other bonded Ru atom and the Te atom of a bridging TeAr ligand occupy equatorial sites, and the Te atom of the other bridging TeAr ligand and a P atom of the bridging dppm ligand are in <i>trans </i>positions. Thus, in complex <b>1</b>, the Te atom of one TeAr group lies in the Ru₂P₂ plane while that of the second TeAr group at a point nearly perpendicular to this plane, making the two TeAr groups nonequivalent but keeping the two P atoms of the bridging dppm ligand in equivalent positions.